SELECT * FROM question_mgmt as q WHERE id=1779 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=57 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Solutions calculate the osmotic pressure in pascals exerted

Question:

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.

Answer:

It is given that:

Volume of water, V= 450 mL = 0.45 L

Temperature, T = (37 + 273)K = 310 K

Number of moles of the polymer,

n = 1 / 185000 mol

We know that:

Osmotic pressure, 

 

= 1/185000 mol X 1/0.45L X 8.314 X 103 Pa L K-1mol-1 X 310K 

 

= 30.98 Pa = 31 Pa (approximately)


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