SELECT * FROM question_mgmt as q WHERE id=2087 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=62 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry The p-Block Elements arrange the following in the order of property ind

Question:

Arrange the following in the order of property indicated for each set:

 

(i) F2, Cl2, Br2, I2- increasing bond dissociation enthalpy.

 

(ii) HF, HCl, HBr, HI - increasing acid strength.

 

(iii) NH3, PH3, AsH3, SbH3, BiH3- increasing base strength.

Answer:

(i) Bond dissociation energy usually decreases on moving down a group as the atomic size increases. However, the bond dissociation energy of F2 is lower than that of Cl2 and Br2. This is due to the small atomic size of fluorine. Thus, the increasing order for bond dissociation energy among halogens is as follows:

I2< F2< Br2< Cl2

 

(ii) HF < HCl < HBr < HI

The bond dissociation energy of H-X molecules where X = F, Cl, Br, I, decreases with an increase in the atomic size. Since H-I bond is the weakest, HI is the strongest acid.

 

(iii) BiH3 < SbH3 < AsH3 < PH3 < NH3

On moving from nitrogen to bismuth, the size of the atom increases while the electron density on the atom decreases. Thus, the basic strength decreases.


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