A sample of drinking water was found to be severely contaminated with chloroform (CHCl3) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass):
(i) express this in percent by mass
(ii) determine the molality of chloroform in the water sample.
1) 15 ppm means : 15 parts per million(106) of the solutions
So, Percent by mass = (mass of chloroform / total mass) x 100
= (15 / 106) x 100
= 1.5 x 10-3 %
2) Molality Mass of chloroform = 15 g
Molar mass of chloroform (CHCl3) = 1 × 12 + 1 × 1 + 3 × 35.5
= 119.5 g mol - 1
Moles of chloroform = 15 / 119.5 = 0.1255 mol
Mass of water = 106
Therefore molality = (moles of chloroform / mass of water ) x 1000
= (0.1255 / 106) x 1000
= 1.255 x 10-4 m
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 9: A sample of drinking water was found to be severely contaminated with chloroform (CHCl3) supposed to....
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Y u haven't considered the weight of solvent in second part as (10^6-15) grams?
Sukriya