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  • Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b).Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.

Primary alkyl halide C4H9Br (a) reacted | Class 12 Chemistry Chapter Haloalkanes and Haloarenes, Haloalkanes and Haloarenes NCERT Solutions

Q21.

Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b).Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.

There are two primary alkyl halides having the formula, C4H9Br. They are n - bulyl bromide and isobutyl bromide.

Therefore, compound (a) is either n-butyl bromide or isobutyl bromide.

Now, compound (a) reacts with Na metal to give compound (b) of molecular formula, C8H18, which is different from the compound formed when n-butyl bromide reacts with Na metal. Hence, compound (a) must be isobutyl bromide.

Thus, compound (d) is 2, 5-dimethylhexane.

It is given that compound (a) reacts with alcoholic KOH to give compound (b). Hence, compound (b) is 2-methylpropene.

Also, compound (b) reacts with HBr to give compound (c) which is an isomer of (a). Hence, compound (c) is 2-bromo-2-methylpropane.

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What is the correct answer to: Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b).Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.?

There are two primary alkyl halides having the formula, C4H9Br. They are n - bulyl bromide and isobutyl bromide.



Therefore, compound (a) is either n-butyl bromide or isobutyl bromide.

Now, compound (a) reacts w...

How do you solve Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b).Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions. step by step?

Step-by-step explanation:
• There are two primary alkyl halides having the formula, C4H9Br
• They are n - bulyl bromide and isobutyl bromide


What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Rahul
Class · · , · Feb 06, 2023
Koh se kon react krega
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shilpakumari
Class · · , · Sep 19, 2019
thaanks
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Suman Raj
Class · · , · Jun 17, 2019
Something is wrong in last reaction.
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HPK
Class · · , · Mar 09, 2019
Superb😍
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nidhi
Class · · , · Mar 07, 2019
thank u...
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jyothy I
Class · · , · Mar 06, 2019
Thwnx
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Nishant Sharma
Class · · , · Sep 15, 2018
There is a correction in there. It is written that -"compound (a) reacts with Na metal to give compound (b) of molecular formula, C8H18" but it should be "compound (a) reacts with Na metal to give compound (d) of molecular formula, C8H18"
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