Copper crystallises into a fcc lattice with edge length 3.61 x 10-8cm. Show that the calculated density is in agreement with its measured value of 8.92 g cm-3.
In fcc lattice Z= 4
Atomic mass M = 63.5
a = 3.61x10-8
Therefore from the formula density = ZxM/a3 x N0
We get density = 4x 63.5/3.61x10-8 x 6.022 x1023
= 8.96 gcm-3.
The value is approximately equal to 8.92.
The rate constant for the decomposition of N2O5 at various temperatures is given below:
T/°C |
0 | 20 | 40 | 60 | 80 |
105 X K /S-1 |
0.0787 | 1.70 | 25.7 | 178 | 2140 |
Draw a graph between ln k and 1/T and calculate the values of A and Ea.
Predict the rate constant at 30 º and 50 ºC.
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 15: Copper crystallises into a fcc lattice with edge length 3.61 x 10-8cm. Show that the calculated dens....
Comments
Atomic mass is not give than how u have calculated