The rate constant for the decomposition | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Question:

The rate constant for the decomposition of N2O5 at various temperatures is given below:

T/°C

0 20 40 60 80

105 X K /S-1

0.0787 1.70 25.7 178 2140

Draw a graph between ln k and 1/T and calculate the values of A and Ea.

Predict the rate constant at 30 º and 50 ºC.

 

Answer:

From the given data, we obtain

T/°C 0 20 40 60 80

T/K

273 293 313 333 353
1/T / k-1

3.66×10 - 3

3.41×10 - 3

3.19×10 - 3

3.0×10 - 3

2.83 ×10 - 3

105 X K /S-1 0.0787 1.70 25.7 178 2140
In k -7.147 -4.075 -1.359 -0.577 3.063

Slope of the line,

In k= - 2.8

Therefore, k = 6.08x10-2s-1

Again when T = 50 + 273K = 323K,

1/T = 3.1 x 10-3 K

In k = - 0.5

Therefore, k = 0.607 s-1

 


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Comments

  • Jiya
  • 2019-06-22 20:04:14

Gud


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 22: The rate constant for the decomposition of N2O5 at various temperatures is given below: ....