The decomposition of hydrocarbon follows the equation
k = (4.5 x 1011 s-1) e-28000 K/T
Calculate Ea.
The given equation is
k = (4.5 x 1011 s-1) e-28000 K/T (i)
Arrhenius equation is given by,
k= Ae -Ea/RT (ii)
From equation (i) and (ii), we obtain
Ea / RT = 28000K / T
⇒ Ea = R x 28000K
= 8.314 J K - 1mol - 1× 28000 K
= 232792 J mol - 1
= 232.792 kJ mol - 1
The following results have been obtained during the kinetic studies of the reaction: 2A + B → C + D
Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate of formation of D/mol L - 1 min - 1 |
I | 0.1 | 0.1 |
6.0 × 10 - 3 |
II | 0.3 | 0.2 |
7.2 × 10 - 2 |
III | 0.3 | 0.4 |
2.88 × 10 - 1 |
IV | 0.4 | 0.1 |
2.40 × 10 - 2 |
Determine the rate law and the rate constant for the reaction.
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 26: The decomposition of hydrocarbon follows the equation k = (4.5 x 1011 s-1) e-28000 K/T Calcula....
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