The decomposition of hydrocarbon follows | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Question:

The decomposition of hydrocarbon follows the equation

k = (4.5 x 1011 s-1) e-28000 K/T

Calculate Ea.

Answer:

The given equation is

k = (4.5 x 1011 s-1) e-28000 K/T           (i)

Arrhenius equation is given by,

k= Ae -Ea/RT                                                (ii)

From equation (i) and (ii), we obtain

E/ RT  =  28000K / T

⇒ E= R x 28000K 

= 8.314 J K - 1mol - 1× 28000 K

= 232792 J mol - 1

= 232.792 kJ mol - 1


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 26: The decomposition of hydrocarbon follows the equation k = (4.5 x 1011 s-1) e-28000 K/T Calcula....