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For the decomposition of azoisopropane to hexane and nitrogen at 543 K...

For the decomposition of azoisopropane t | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Question:

For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtained.

t (sec)	P(mm of Hg)
0	35.0
360	54.0
720	63.0

Calculate the rate constant

Answer:

The decomposition of azoisopropane to hexane and nitrogen at 543 K is represented by the following equation.

After time, t, total pressure, P_t = (P_º - p) + p + p

⇒ P_t = (P_º + p)

⇒ p = P_t - P_º

therefore, P_º - p = P_º- P_t - P_º

= 2 P_º- P_t

For a first order reaction,

k = 2.303/t Log P_º/ P_º- p

= 2.303/t Log P_º/ 2 P_º- P_t

When t = 360 s, k = 2.303 / 360s log 35.0 / 2x35.0 - 54.0

= 2.175 × 10 ^{- 3} s ^{- 1}

When t = 720 s, k = 2.303 / 720s log 35.0 / 2x35.0 - 63.0

= 2.235 × 10 ^{- 3} s ^{- 1}

Hence, the average value of rate constant is

k = (2.175 × 10 ^{- 3}+ 2.235 × 10 ^{- 3} ) / 2 s ^{- 1}

= 2.21 × 10 ^{- 3}s^{- 1}

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Comments

Gnkp
2019-11-17 14:02:52

Approval hmmm!

Jishan
2019-08-17 09:27:55

Thanx alot

Stuti
2019-07-01 21:39:29

Thankyou !! Helped alot!!

Ayush
2019-06-07 19:02:19

Thnx alot

Subhadeep Raj
2019-03-06 07:59:09

Thanks for your help

Agrima
2019-01-27 17:24:18

Thank u

Janhavi khalatkar
2018-11-12 23:50:35

Ohhhh..thanks

Somya
2018-09-25 17:47:50

Thanku

Arnav Shivam
2018-07-26 14:55:59

ThnkZzzzzzzzx u....

Rajat garg
2018-06-16 10:48:57

Thanks for your help

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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 20: For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtai....

For the decomposition of azoisopropane t | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

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