What is shape selective catalysis? | Class 12 Chemistry Chapter Surface Chemistry, Surface Chemistry NCERT Solutions

Question:

Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4

Answer:

Molecules are made up of atoms & are  quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus  molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.

(i) H2O:

The molecular mass of water, H2O

= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)

= [2(1.0084) + 1(16.00 u)]

= 2.016 u + 16.00 u

= 18.016

= 18.02 u

(ii) CO2:

The molecular mass of carbon dioxide, CO2

= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)

= [1(12.011 u) + 2 (16.00 u)]

= 12.011 u + 32.00 u

= 44.01 u

(iii) CH4:

The molecular mass of methane, CH4

= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)

= [1(12.011 u) + 4 (1.008 u)]

= 12.011 u + 4.032 u

= 16.043 u


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Comments

  • Xyz
  • 2019-09-06 16:30:40

Thanks 😊


  • Xyz
  • 2019-09-06 16:29:59

Thanks 😊


  • Divya
  • 2019-07-04 20:27:18

Thanks for the answer


  • Ankit Roshan
  • 2019-06-23 21:30:58

Thanks for the Answer Helpful


  • Divya
  • 2019-06-21 23:07:07

Thanks for the helpful one


  • Shivani
  • 2019-06-16 21:19:08

It's amazing answer thanks for help us


  • Aditi
  • 2019-03-12 15:06:13

It's superb


  • Prakshi
  • 2019-03-10 07:48:28

Thanks a lot made things a lot easier


  • Nilesh yadav
  • 2018-05-16 17:40:02

Good answer but if some pictures of this catalysis also seen so it is much better


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 22: What is shape selective catalysis?....