Glucose or sucrose are soluble in water | Class 12 Chemistry Chapter Biomolecules, Biomolecules NCERT Solutions

Q1.

Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.

For any compound to be water soluble, it should develop dipoles (partial negative and partial positive charges) at the two ends of compound. The development of charges results in the formation of hydrogen bond between the water molecule and the compound. The development of charges at two ends is due to the difference in the electronegativity between two atoms. The atom with higher electronegativity will acquire negative charge while the atom with lower electronegativity will acquire positive charge. A glucose molecule contains five –OH (highly electronegative) groups while a sucrose molecule contains eight −OH groups. Thus, glucose and sucrose undergo extensive H-bonding with water. Hence, these are soluble in water.

But cyclohexane and benzene do not contain −OH groups. They contain only carbon and hydrogen atoms, as a result the dipole developed is very weak in nature and hence the hydrogen bond formed is not strong. Hence, they cannot undergo H-bonding with water and thus are insoluble in water.

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This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

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What is the correct answer to: Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.?

For any compound to be water soluble, it should develop dipoles (partial negative and partial positive charges) at the two ends of compound. The development of charges results in the formation of hydrogen bond between th...

How do you solve Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain. step by step?

Step-by-step explanation:
• For any compound to be water soluble, it should develop dipoles (partial negative and partial positive charges) at the two ends of compound
• The development of charges results in the formation of hydrogen bond between the water molecule and the compound
• The development of charges at two ends is due to the difference in the electronegativity between two atoms
• The atom with higher electronegativity will acquire negative charge while the atom with lower electronegativity will acquire positive charge
• A glucose molecule contains five –OH (highly electronegative) groups while a sucrose molecule contains eight −OH groups

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Oishi Sinha
Class · · , · Dec 08, 2019
Perfect answer......thank you!
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Mukunda
Class · · , · Apr 08, 2019
Nice explanation
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Unknown
Class · · , · Feb 17, 2019
Useful answer
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