How much time would it take to distribute one Avogadro number of wheat grains, if 1010 grains are distributed each second?
We know , Avogadro number = 6.023 × 1023
Therefore , time taken for distributing the grains
= (6.023 × 1023 x 1) / 1010 = 6.023 x 1013 s
By Converting these seconds into years, we get
= (6.023 x 1013) / (60 x60x24x365)
= 1,90,9800 y
Hence, the time taken would be 1.909 x 106 years.
The first (ΔiH1) and the second (ΔiH) ionization enthalpies (in kJ mol–1) and the (ΔegH) electron gain enthalpy (in kJ mol–1) of a few elements are given below:
Elements | ΔiH1 | ΔiH | ΔegH |
I | 520 | 7300 | -60 |
II | 419 | 3051 | -48 |
III | 1681 | 3374 | -328 |
IV | 1008 | 1846 | -295 |
V | 2372 | 5251 | +48 |
VI | 738 | 1451 | -40 |
Which of the above elements is likely to be :
(a) the least reactive element.
(b) the most reactive metal.
(c) the most reactive non-metal.
(d) the least reactive non-metal.
(e) the metal which can form a stable binary halide of the formula MX2, (X=halogen).
(f) the metal which can form a predominantly stable covalent halide of the formula MX (X=halogen)?
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 14: How much time would it take to distribute one Avogadro number of wheat grains, if 1010 grains are di....
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Why the Avogadro's no. Divide by 10^10
This ans is correct . But it can be more explained clearly
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How to convert seconds into years
Respected sir If a man counts four grain of wheat each second than how much time he takes to count one mol of wheat grain?