2.9 g of a gas at 95 °C occupied the | Class 11 Chemistry Chapter States of Matter, States of Matter NCERT Solutions

Question:

2.9 g of a gas at 95 °C occupied the same volume as 0.184 g of dihydrogen at 17 °C, at the same pressure. What is the molar mass of the gas?

Answer:

From the gas equation,

PV = (w/M) RT

Substituting the given data in the gas equation, we get

PV = (2.9 / M) x R x 368

&

PV = (0.184 / 2) x R x 290

From these two equation, we can write

(2.9 / M) x R x 368 = (0.184 / 2) x R x 290

By, striking throug R from both side, we get

(2.9 / M) x 368 = (0.184 / 2) x 290

Or

(2.9 / M)   =  (0.092 X 290) / 368

Or

M  = 2.9 x 368 / 0.092 x 290

= 40 g/mol

Hence, the molar mass of the gas is 40 g mol–1.


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Comments

  • shaham
  • 2019-09-14 20:25:42

plz specify


  • shaham
  • 2019-09-14 19:53:38

why are there so many 'or's , its little confusing


  • Uc
  • 2018-12-12 06:30:00

39.67


  • vatsa
  • 2018-10-26 16:06:01

38.94g/mol


  • Amal dev
  • 2018-10-25 19:49:49

What is w÷M i dont hear this


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: 2.9 g of a gas at 95 °C occupied the same volume as 0.184 g of dihydrogen at 17 °C, at the s....