It has been found that the pH of a 0.01M solution of an organic acid is 4.15. Calculate the concentration of the anion, the ionization constant of the acid and its pKa.
Let the organic acid be HA.
⇒ HA ↔ H+ + A-
Concentration of HA = 0.01 M
pH = 4.15
-log[H+] = 4.15
[H+] = 7.08x10-5
Now, Ka = [H+] [A-] / [HA]
[H+] = [A-] = 7.08x10-5
[HA] = 0.01
Then,
Ka = 7.08x10-5 x 7.08x10-5 / 0.01
Ka = 5.01x10-7
pKa = -log Ka
= -log(5.01x10-7)
pKa = 6.3001
Following results are observed when sodium metal is irradiated with different wavelengths.
Calculate (a) threshold wavelength and, (b) Planck’s constant.
λ (nm) | 500 | 450 |
400 |
v × 10–5 (cm s–1) | 2.55 | 4.35 | 5.35 |
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 47: It has been found that the pH of a 0.01M solution of an organic acid is 4.15. Calculate the concentr....
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