A point charge +10 μC is a distance 5 | Class 12 Physics Chapter Electric Charges and Field, Electric Charges and Field NCERT Solutions

Question:

A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in Fig. 1.34. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with edge 10 cm.)

Answer:

The square can be considered as one face of a cube of edge 10 cm with a centre where charge q is placed. According to Gauss’s theorem for a cube, total electric flux is through all its six faces.

Hence, electric flux through one face of the cube i.e., through the square,

Where, ∈0 = Permittivity of free space

= 8.854 × 10−12 N−1C2 m−2 q = 10 μC = 10 × 10−6 C

= 1.88 × 105 N m2 C−1

Therefore, electric flux through the square is 1.88 × 105 N m2 C−1.


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Comments

  • Karisa
  • 2021-12-13 01:11:42

Nice 👍


  • Divya
  • 2021-01-10 20:08:34

Very helpful for me ☺️☺️ thanks 😊


  • SPBhagyam
  • 2020-07-30 20:28:32

Thakzzz


  • SPBhagyam
  • 2020-07-30 20:27:56

Gud


  • Ritika Suryavanshi
  • 2020-05-22 18:38:46

Proved to be very helpful


  • Anamika
  • 2019-11-24 15:34:39

Thnq 😊


  • Pratisha
  • 2019-06-18 22:30:02

Can we solve this without using Gauss law?? ( By using EdScos0 alone)


  • Arvendra dhakar
  • 2018-12-25 07:29:22

Thanks a lot


  • Shivangi srivastava
  • 2018-07-01 12:04:54

Thanks


  • Miracle
  • 2017-06-16 13:41:37

Two charges q1= 10uc and q2= -12uc are within a spherical surface of radius 10cm. What is the total flux through the surface ?


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as ....