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Read MoreA conducting sphere of radius 10 cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is 1.5 × 103 N/C and points radially inward, what is the net charge on the sphere?
Electric field intensity (E) at a distance (d) from the centre of a sphere containing net charge q is given by the relation,

Where, q = Net charge = 1.5 × 103 N/C
d = Distance from the centre = 20 cm = 0.2 m
∈0 = Permittivity of free space
And,
= 9 × 109 N m2 C−2
∴

= 6.67 × 109 C
= 6.67 nC
Therefore, the net charge on the sphere is 6.67 nC.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Electric field intensity (E) at a distance (d) from the centre of a sphere containing net charge q is given by the relation,
Where, q = Net charge = 1.5 × 103 N/C
d = Distance from the centre = 20 cm = 0....
Step-by-step explanation:
• Electric field intensity (E) at a distance (d) from the centre of a sphere containing net charge q is given by the relation,
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•
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• Where, q = Net charge = 1
This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.
This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.
Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.
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Student Discussion
It is written...
Where,q=net charge=1.5*10³N/C.
Here, 1.5*10³ is the value of E(electric field intensity.
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