A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10-12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
Capacitance between the parallel plates of the capacitor, C = 8 pF
Initially, distance between the parallel plates was d and it was filled with air. Dielectric constant of air, k = 1
Capacitance, C, is given by the formula,
Where, A = Area of each plate
= Permittivity of free space
If distance between the plates is reduced to half, then new distance, d' = d / 2
Dielectric constant of the substance filled in between the plates, = 6
Hence, capacitance of the capacitor becomes
Taking ratios of equations (i) and (ii), we obtain
Therefore, the capacitance between the plates is 96 pF.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10-12 F). Wh....
Comments
The capacitance of a parallel plate capacitor having air between its plates is 10 µf if the distance between the plates is reduced to half and the medium between plates is replaced by a medium of dielectric constant k=5, then find the value how much increase or decrease in the capacitance of the capacitor.
Thank you...ð
so nice of u
thank u for the clerety
Thanks for this nswer
Thanks a lotð
Thanks a lotð
Thnk u very helpful n good answer
Thank you
Akansha