A 600 pF capacitor is charged by a 200 V | Class 12 Physics Chapter Electrostatic Potential and Capacitance, Electrostatic Potential and Capacitance NCERT Solutions

Q11.

A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process?

Capacitance of the capacitor, C = 600 pF

Potential difference, V = 200 V

Electrostatic energy stored in the capacitor is given by,

If supply is disconnected from the capacitor and another capacitor of capacitance C = 600 pF is connected to it, then equivalent capacitance (C') of the combination is given by,

New electrostatic energy can be calculated as

Loss in electrostatic enegy = E - E'

                                        = 1.2 x 10-5  -  0.6 x 10-5

                                        = 0.6 x 10-5

                                        = 6 x 10-6 J 

Therefore, the electrostatic energy lost in the process is 6 x 10-6 J.  

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What is the correct answer to: A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process??

Capacitance of the capacitor, C = 600 pF

Potential difference, V = 200 V

Electrostatic energy stored in the capacitor is given by,



If supply is disconnected from the capacitor and another capacitor of capaci...

How do you solve A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process? step by step?

Step-by-step explanation:
• Capacitance of the capacitor, C = 600 pF
•
• Potential difference, V = 200 V
•
• Electrostatic energy stored in the capacitor is given by,

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Anjali Kashyap
Class · · , · Jul 23, 2019
Thank you
👍 👎 Reply
Adithya
Class · · , · Jun 23, 2019
common potential =c1c2\\c1+c2
👍 👎 Reply
Deepika
Class · · , · Jun 14, 2019
How can we now that it is connected in series
👍 👎 Reply
Ameer Navas
Class · · , · Jun 08, 2019
It is parallel not series.
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Gode Basar
Class · · , · May 10, 2019
How can we know that the capacitors are connected in series?
👍 👎 Reply
Nandini
Class · · , · May 08, 2019
How can we conclude that capacitors are in series
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Vibhor Singh
Class · · , · May 23, 2018
In this question it is not written that uncharged capacitor is connected in series then how you take in series according to the solution??
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vinay
Class · · , · Feb 28, 2018
what if the unchanged capacitor is connected to parallel with it
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