What is the force between two small charged spheres having charges of 2 x 10-7 C and 3 x 10-7 C placed 30 cm apart in air?
Repulsive force of magnitude 6 × 10 - 3 N
Charge on the first sphere, q1 = 2 × 10 - 7 C
Charge on the second sphere, q2 = 3 × 10 - 7 C
Distance between the spheres, r = 30 cm = 0.3 m
Electrostatic force between the spheres is given by the relation,
Where, ∈0 = Permittivity of free space
Hence, force between the two small charged spheres is 6 × 10 - 3 N. The charges are of same nature. Hence, force between them will be repulsive.
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Comments
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This answer is correctâ âââ ââ âââ thank you so many answers are posted sir and mamdam
Answer na aabit hau yrrr 10 ke power me garbara jaite huk
.3*.3=0.09 so 0.09 se 9 ko divide krne par 100 ayega
6.033x10^-5 ye answer aayega.
But the answer is perfect in nootan aur calculater bhi 10^-3 dikbha rahi hain.
Wrong Answer Right Answer= 1â¢8Ã10 ka power -3
I m getting 5.4 into ten to the power -4
Heee -3 kese aya 5 ata hai am confused plz reply me fast ok how it come ....