A circular coil of wire consisting of 10 | Class 12 Physics Chapter Moving Charges and Magnetism, Moving Charges and Magnetism NCERT Solutions

Q1. A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil?

Number of turns on the circular coil, n = 100

Radius of each turn, r = 8.0 cm = 0.08 m

Current flowing in the coil, I = 0.4 A

Magnitude of the magnetic field at the centre of the coil is given by the relation,

| B | = μ0 2πnI / 4π r

Where,

μ= Permeability of free space

= 4π × 10–7 T m A–1

| B | = 4π x 10-7 x 2π x 100 x 0.4 / 4π x 0.08

       = 3.14 x 10-4 T

Hence, the magnitude of the magnetic field is 3.14 × 10–4 T.

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Important Questions & Answers

What is the correct answer to: A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil??

Number of turns on the circular coil, n = 100

Radius of each turn, r = 8.0 cm = 0.08 m

Current flowing in the coil, I = 0.4 A

Magnitude of the magnetic field at the centre of the...

How do you solve A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil? step by step?

Step-by-step explanation:
• Number of turns on the circular coil, n = 100

• Radius of each turn, r = 8
• 0 cm = 0
• 08 m

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Saniya
Class · · , · Feb 15, 2023
Thanks 😊
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deepto
Class · · , · Sep 24, 2020
thanks a lot
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Ritesh
Class · · , · Dec 03, 2019
Thank you bhut hard...👌😁
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Dipu Dileep
Class · · , · Oct 31, 2019
Thanks 😊😊😊😊✌🏼✌🏼✌🏼
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Kavya
Class · · , · Jul 20, 2019
Thank you
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Saima
Class · · , · Mar 01, 2019
Thankyou
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Ankit kumar
Class · · , · Aug 03, 2018
Question is incomplete because the value of mean radius is not given.but anyway you use the formula to find magnetic field at the center of coil that B= munot NI divided by 2 multiply mean radius
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