The electrostatic force on a small spher | Class 12 Physics Chapter Electric Charges and Field, Electric Charges and Field NCERT Solutions

Q2.

The electrostatic force on a small sphere of charge 0.4 μC due to another small sphere of charge − 0.8 μC in air is 0.2 N.

(a) What is the distance between the two spheres?

(b) What is the force on the second sphere due to the first?

 (a) Electrostatic force on the first sphere, F = 0.2 N

Charge on this sphere, q1 = 0.4 μC = 0.4 × 10−6 C

Charge on the second sphere, q2 = − 0.8 μC = − 0.8 × 10−6 C

Electrostatic force between the spheres is given by the relation,

F space equals space fraction numerator q subscript 1 q subscript 2 over denominator 4 straight pi element of subscript 0 straight r squared end fraction space
A n d comma space fraction numerator 1 over denominator 4 straight pi element of subscript 0 end fraction space equals space 9 space cross times space 10 to the power of 9 space N space m squared space C to the power of minus 2 end exponent

Where, ∈0 = Permittivity of free space

r squared space equals space fraction numerator q subscript 1 q subscript 2 over denominator 4 straight pi element of subscript 0 straight F end fraction
space space space space equals fraction numerator 0.4 space cross times 10 to the power of minus 6 end exponent space cross times 8 space cross times 10 to the power of minus 6 end exponent space cross times 9 space cross times 10 to the power of 9 over denominator 0.2 end fraction
space space space space equals space 144 space cross times space 10 to the power of minus 4 end exponent
r space equals space square root of 144 space cross times 10 to the power of minus 4 end exponent end root
space space space equals.12 space m space

The distance between the two spheres is 0.12 m.

(b) Both the spheres attract each other with the same force. Therefore, the force on the second sphere due to the first is 0.2 N.

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Important Questions & Answers

What is the correct answer to: The electrostatic force on a small sphere of charge 0.4 μC due to another small sphere of charge − 0.8 μC in air is 0.2 N. (a) What is the distance between the two spheres? (b) What is the force on the second sphere due to the first??

 (a) Electrostatic force on the first sphere, F = 0.2 N

Charge on this sphere, q1 = 0.4 μC = 0.4 × 10−6 C

Charge on the second sphere, q2 = − 0.8 μC =...

How do you solve The electrostatic force on a small sphere of charge 0.4 μC due to another small sphere of charge − 0.8 μC in air is 0.2 N. (a) What is the distance between the two spheres? (b) What is the force on the second sphere due to the first? step by step?

Step-by-step explanation:
•  (a) Electrostatic force on the first sphere, F = 0
• 2 N
•
• Charge on this sphere, q1 = 0
• 4 μC = 0

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Gaurav
Class · · , · May 03, 2023
u have give answer that why taking 8c instead of 0.8
👍 👎 Reply
Sahla kanz
Class · · , · Jul 20, 2020
Super
👍 👎 Reply
krish
Class · · , · Dec 10, 2019
this is very useful to me thanks for this
👍 👎 Reply
Ankur mishra
Class · · , · Aug 22, 2019
Very nice
👍 👎 Reply
Lalisa
Class · · , · Aug 19, 2019
Very helpful
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Amit
Class · · , · Apr 30, 2019
Helpful but u haven't given the reason that why u put 8 instead of .8
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Swati joshi
Class · · , · Apr 26, 2019
It's really very helpful
👍 👎 Reply
Minjae
Class · · , · Apr 24, 2019
Ha! Thanks for this so simple it was and 0.8 or 8 no problem take 9.0 if u use o.8 or vice versa
👍 👎 Reply
Anmol
Class · · , · Apr 10, 2019
Why taking 8 instead of .8
👍 👎 Reply
Kaamil
Class · · , · Mar 27, 2019
Very good n thank you for help
👍 👎 Reply

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