How to Use NCERT Solutions Effectively
Learn the best strategies to make the most of NCERT solutions for your exam preparation.
Read MoreCalculate the molarity of each of the following solutions:
(a)30 g of Co(NO3)2. 6H2O in 4.3 L of solution
(b)30 mL of 0.5 M H2SO4 diluted to 500 mL.
Molarity is given by:
Molarity = moles of solute / Volume of solution in litre
(a) Molar mass of Co(NO3)2.6H2O
= 59 + 2 (14 + 3 × 16) + 6 × 18 = 291 g mol - 1
∴Moles of Co(NO3)2.6H2O = 30 / 291 mol
= 0.103 mol
Therefore, molarity = 0.103 mol / 4.3 L
= 0.024 M
(b) Number of moles present in 1000 mL of 0.5 M H2SO4 = 0.5 mol
∴ Number of moles present in 30 mL of 0.5 M H2SO4 = (0.5 X 30 ) / 1000 mol
= 0.015 mol
Therefore, molarity = 0.015 mol / 0.5 L
= 0.03 M
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
| Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate/mol L - 1 min - 1 |
| I | 0.1 | 0.1 |
2.0 × 10 - 2 |
| II | -- | 0.2 |
4.0 × 10 - 2 |
| III | 0.4 | 0.4 | -- |
| IV | -- | 0.2 |
2.0 × 10 - 2 |
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Molarity is given by:
Molarity = moles of solute / Volume of solution in litre
(a) Molar mass of Co(NO3)2.6H2O
= 59 + 2 (14 + 3 × 16) + 6 × 18 = 291 g mol - 1
∴Moles of Co(NO3)2.6H2O&...
Step-by-step explanation:
• Molarity is given by:
•
• Molarity = moles of solute / Volume of solution in litre
•
• (a) Molar mass of Co(NO3)2
This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.
This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.
Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.
Stay updated with our latest educational content and study tips
Student Discussion
Be the first to comment.
ADD NEW COMMENT