At 300 K, 36 g of glucose present in a l | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Question:

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

Answer:

Here we have given

π1= 4.98

π2 = 1.52

C1 = 36/180

C2 = ? (we have to find)

Now according to van’t hoff equation

Π = CRT

Putting the values in above equation,we get

4.98 = 36/180RT ------------------------1

1.52 = c2RT       ------------------------2

Now dividing equation 2 by 1 ,we get

(c2 x 180) / 36 = 1.52 / 4.98

or

c2 = 0.061

Therefore concentration of 2nd solution is 0.061 M


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Comments

  • Nevil
  • 2019-08-24 14:40:33

Nyc


  • Uzair shaikh
  • 2019-06-09 15:29:16

C1=mole/volume=weight/molecular weight × 1/volume = 36/180 × 1/1


  • manisha
  • 2019-05-28 13:09:30

what is the meaning of writing C1= 36/180 but its real value is 36g


  • Khushi
  • 2019-05-15 22:23:19

How can write 36/180


  • Obd
  • 2019-05-14 21:29:20

Sir its 0.061


  • RAUSHAN KUMAR
  • 2019-04-10 20:42:28

How write 36/180


  • Chandan Sharma
  • 2018-09-17 09:11:30

Sorry... The answer of this question is... 0.06 not 0.006


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 22: At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If....