Calculate the mass of ascorbic acid (Vitamin C, C6H8O6) to be dissolved in 75 g of acetic acid to lower its melting point by 1.5°C. Kf= 3.9 K kg mol-1.
Mass of acetic acid, w1= 75 g Molar mass of ascorbic acid (C6H8O6),
M2= 6 × 12 + 8 × 1 + 6 × 16
= 176 g mol - 1
Lowering of melting point, ΔTf = 1.5 K
We know that:
= (1.5 x 176 x 75) / (3.9 x 1000)
= 5.08 g (approx)
Hence, 5.08 g of ascorbic acid is needed to be dissolved.
The rate constant for the decomposition of N2O5 at various temperatures is given below:
T/°C |
0 | 20 | 40 | 60 | 80 |
105 X K /S-1 |
0.0787 | 1.70 | 25.7 | 178 | 2140 |
Draw a graph between ln k and 1/T and calculate the values of A and Ea.
Predict the rate constant at 30 º and 50 ºC.
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 11: Calculate the mass of ascorbic acid (Vitamin C, C6H8O6) to be dissolved in 75 g of acetic acid to lo....
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Vfvdhvs
To is in °C in question.