The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
Here,
K = 0.693 / t½
= 0.693 / 5730 years-1
It is known that,
= 1845 years (approximately)
Hence, the age of the sample is 1845 years.
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 14: The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood....
Comments
My answer is 1919
How 0.693 come
The answer will be 1910 yrs T=1/KÃln(A°/A) Also, 1/K=t(1/2)/ln2 So, T=[t(1/2)/ln2]Ãln(A°/A) T= 5730yrs Ã(log5-log4/log3)
All radioactive decay are of 1st order reaction. So zero order can't be taken.
What if zero order?
radioactive decay is first order reaction & half-life of first order =0.693/k first you will find the value of k then put in formule and use log value of log100/80=log5/4=log5-log4
Hii how this answer came out to be 1845