The half-life for radioactive decay of 1 | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Question:

The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.

Answer:

Here,

K = 0.693 / t½

= 0.693 / 5730 years-1

It is known that,

= 1845 years (approximately)

Hence, the age of the sample is 1845 years.


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Comments

  • Aqeel Ahmad
  • 2019-08-01 20:08:34

My answer is 1919


  • Gayu
  • 2019-05-27 21:53:58

How 0.693 come


  • Kislay
  • 2019-03-08 22:33:16

The answer will be 1910 yrs T=1/K×ln(A°/A) Also, 1/K=t(1/2)/ln2 So, T=[t(1/2)/ln2]×ln(A°/A) T= 5730yrs ×(log5-log4/log3)


  • Lakshmi
  • 2019-02-10 11:17:28

All radioactive decay are of 1st order reaction. So zero order can't be taken.


  • Dvbhav
  • 2018-07-31 22:56:08

What if zero order?


  • abi namdev
  • 2018-02-12 07:05:13

radioactive decay is first order reaction & half-life of first order =0.693/k first you will find the value of k then put in formule and use log value of log100/80=log5/4=log5-log4


  • Raniya
  • 2017-12-29 07:07:34

Hii how this answer came out to be 1845


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 14: The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood....