The half-life for radioactive decay of 1 | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

Q14.

The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.

Here,

K = 0.693 / t½

= 0.693 / 5730 years-1

It is known that,

= 1845 years (approximately)

Hence, the age of the sample is 1845 years.

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Important Questions & Answers

What is the correct answer to: The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.?

Here,

K = 0.693 / t½

= 0.693 / 5730 years-1

It is known that,



= 1845 years (approximately)

Hence, the age of the sample is 1845 years....

How do you solve The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample. step by step?

Step-by-step explanation:
• Here,

• K = 0
• 693 / t½

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Aqeel Ahmad
Class · · , · Aug 01, 2019
My answer is 1919
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Gayu
Class · · , · May 27, 2019
How 0.693 come
👍 👎 Reply
Kislay
Class · · , · Mar 08, 2019
The answer will be 1910 yrs
T=1/K×ln(A°/A)
Also, 1/K=t(1/2)/ln2
So, T=[t(1/2)/ln2]×ln(A°/A)
T= 5730yrs ×(log5-log4/log3)
👍 👎 Reply
Lakshmi
Class · · , · Feb 10, 2019
All radioactive decay are of 1st order reaction. So zero order can't be taken.
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Dvbhav
Class · · , · Jul 31, 2018
What if zero order?
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abi namdev
Class · · , · Feb 12, 2018
radioactive decay is first order reaction & half-life of first order =0.693/k first you will find the value of k then put in formule and use log value of log100/80=log5/4=log5-log4
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Raniya
Class · · , · Dec 29, 2017
Hii how this answer came out to be 1845
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