In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å:
(a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at infinite separation of the electron from proton.
(b) What is the minimum work required to free the electron, given that its kinetic energy in the orbit is half the magnitude of potential energy obtained in (a)?
(c) What are the answers to (a) and (b) above if the zero of potential energy is taken at 1.06 Å separation?
The distance between electron-proton of a hydrogen atom, d = 0.53 Å
Charge on an electron, q1 = - 1.6 ×10 -19 C
Charge on a proton, q2 = +1.6 ×10-19 C
(a) Potential at infinity is zero.
Potential energy of the system, = Potential energy at infinity - Potential energy at distance d
where,
∈0 is the permittivity of free space
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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 Å: (a) Es....
Comments
where is the answers for option b)and c).this was more interesting to me .but now it is too boring l lost my all answers in my mind because of this big mistake.everyone wants the correct and appropriate answer .nit just a solution. so pls dont hesitate us by doing tjis mistake again and again .please
Right answer is2720
Yes
This calculation is false