The storage battery of a car has an emf | Class 12 Physics Chapter Current Electricity, Current Electricity NCERT Solutions

Q1. The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4Ω, what is the maximum current that can be drawn from the battery?

Emf of the battery, E = 12 V

Internal resistance of the battery, r = 0.4 Ω

Maximum current drawn from the battery = I

According to Ohm’s law,

E = Ir

I = E / r 

 = 12 / 0.4 

 = 30 A 

The maximum current drawn from the given battery is 30 A.

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Important Questions & Answers

What is the correct answer to: The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4Ω, what is the maximum current that can be drawn from the battery??

Emf of the battery, E = 12 V

Internal resistance of the battery, r = 0.4 Ω

Maximum current drawn from the battery = I

According to Ohm’s law,

E = Ir

I = E / r&nbsp...

How do you solve The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4Ω, what is the maximum current that can be drawn from the battery? step by step?

Step-by-step explanation:
• Emf of the battery, E = 12 V

• Internal resistance of the battery, r = 0
• 4 Ω

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

ifat shaikh
Class · · , · Nov 25, 2019
it is very helpful for physics lover
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Parul
Class · · , · May 28, 2019
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Viruuuu
Class · · , · Feb 11, 2019
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Axomiya
Class · · , · Feb 06, 2019
Emf of the battery, E = 12 V
Internal resistance of the battery, r =0.4 Ω
Maximum current drawn from the battery = I
According to Ohm’s law,
E = Ir,I = E / r = 12 / 0.4 = 30 A
👍 👎 Reply
sumit jha
Class · · , · Jan 05, 2019
E=12V
R=0.4Ω
I=?
According to ohm's law
E=IR => I=E/R => 12/0.4 => 30A
The max current that can be drawn from the battery is 30A
👍 👎 Reply
Sivani Gupta
Class · · , · Aug 23, 2017
Its helpful for physics lovers...i loved it...
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