SELECT * FROM question_mgmt as q WHERE id=1561 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=57 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Solutions a solution is obtained by mixing 300 g of 25 solu

Question:

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

Answer:

According to question,

300g of 25% solution contains solute = (300 x 25) / 100 = 75g

&

400g of 40% solution contains solute = (400 x 40) / 100 = 160g

Total solute = 75 + 160 = 235g

As given in the question, total solution =300 + 400 = 700g

Percentage of solute in the final solution = (235 x100) / 700 = 33.57%

Percentage of water in the final solution = 100 - 33.5 = 65.43%


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='9' AND ex_no!=0 AND status=1 and id!=1561 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='9' AND ex_no!=0 AND status=1 and id!=1561 ORDER BY last_viewed_on desc limit 0,10

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