If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?
The magnetic field on the axis of the magnet at a distance d1= 14 cm, can be written as:
Where, M = Magnetic moment
μ0= Permeability of free space
H= Horizontal component of the magnetic field at d1
If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.
Hence, the magnetic field at a distance d2, on the equatorial line of the magnet can be written as:
Equating equations (1) and (2), we get:
The new null points will be located 11.1 cm on the normal bisector.
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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 14: If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be l....
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