The number density of free electrons in a copper conductor estimated in Example 3.1 is 8.5 x 1028 m-3. How long does an electron take to drift from one end of a wire 3.0 m long to its other end? The area of cross-section of the wire is 2.0 x 10-6 m2 and it is carrying a current of 3.0 A.
Number density of free electrons in a copper conductor, n = 8.5 × 1028 m - 3 Length of the copper wire, l = 3.0 m
Area of cross-section of the wire, A = 2.0 × 10 - 6 m2
Current carried by the wire, I = 3.0 A, which is given by the relation,
I = nAeVd
Where,
e = Electric charge = 1.6 × 10 - 19 C
Vd = Drift velocity
Therefore, the time taken by an electron to drift from one end of the wire to the other is 2.7 × 104 s.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 13: The number density of free electrons in a copper conductor estimated in Example 3.1 is 8.5 x 1028 m-....
Comments
Is it is correct?
Find out the number of electron
Very dirty
answer value unimaginably large time. Can you please make me understand it ?