A 44 mH inductor is connected to 220 V, | Class 12 Physics Chapter Alternating Current, Alternating Current NCERT Solutions

Question:

A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

Answer:

Inductance of inductor, L = 44 mH = 44 × 10-3 H

Supply voltage, V = 220V

Frequency, ν = 50Hz

Angular frequency, \[\begin{align}\omega = 2\pi v\end{align}\]

Inductive reactance, \begin{align}X_{L}= \omega L = 2\pi vL = 2\pi\times50\times44\times10^{-3} \Omega\end{align}

Rms value of current is given as:

\begin{align}I = \frac{v}{X_{L}}\end{align}

\begin{align} = \frac{220}{2\pi\times50\times44\times 10^{-3}} =15.92A\end{align}

Hence, the rms value of current in the circuit is 15.92 A.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Alternating Current.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

  • Sankar
  • 2020-01-11 11:08:07

Verry good i like you


  • anand
  • 2018-05-08 16:07:44

Question no 3.10 se aage


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in t....