The resistance of a conductivity cell co | Class 12 Chemistry Chapter Electrochemistry, Electrochemistry NCERT Solutions

Question:

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 x 10-3 S cm-1.

Answer:

Given,

Conductivity, k = 0.146 × 10 - 3 S cm - 1

Resistance, R = 1500 Ω

Cell constant = k × R = 0.146 × 10 - 3 × 1500

= 0.219 cm - 1


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Comments

  • Aditya
  • 2020-09-24 10:13:19

Where is question 10


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 9: The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. ....