The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 x 10-3 S cm-1.
Given,
Conductivity, k = 0.146 × 10 - 3 S cm - 1
Resistance, R = 1500 Ω
Cell constant = k × R = 0.146 × 10 - 3 × 1500
= 0.219 cm - 1
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 9: The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. ....
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