A short bar magnet placed with its axis | Class 12 Physics Chapter Magnetism and Matter, Magnetism and Matter NCERT Solutions

Question:

A short bar magnet placed with its axis at 30º with a uniform externalmagnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 x 10-2J. What is the magnitude of magnetic moment of the magnet?

Answer:

Magnetic field strength, B= 0.25 T

Torque on the bar magnet, T= 4.5 ×10-2J

Angle between the bar magnet and the external magnetic field,θ= 30°

Torque is related to magnetic moment (M) as:

T= MB sin θ

Hence, the magnetic moment of the magnet is 0.36 J T-1.


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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: A short bar magnet placed with its axis at 30º with a uniform externalmagnetic field of 0.25 T ....