Find out the value of Kc for each of the | Class 11 Chemistry Chapter Equilibrium, Equilibrium NCERT Solutions

Question:

Find out the value of Kc for each of the following equilibria from the value of Kp:

(i) 2NOCl (g)  ↔  2NO (g) + Cl2 (g);                   Kp  =  1.8 × 10–2 at 500 K

(ii) CaCO3 (s)  ↔  CaO(s) + CO2(g);                  Kp  = 167 at 1073 K

Answer:

(a) The relation between Kp and Kc is given as:

Kp = Kc (RT)Δn

(a) Here, Δn = 3 - 2 = 1

R = 0.0831 barLmol-1K-1

T = 500 K

Kp = 1.8 x 10-2

Now, Kp = Kc (RT)Δn

⇒ Kc  = 1.8 x 10-2  /  (0.0831x500)

         = 4.33 x 10-4 (approx.)

 

(b) Here, Δn = 2 - 1 = 1

R = 0.0831 barLmol-1K-1

T = 1073 K

K= 167

Now, Kp = Kc (RT)Δn

⇒ Kc  = 167 / (0.0831x1073)

         = 1.87 (approx.)


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Equilibrium.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Find out the value of Kc for each of the following equilibria from the value of Kp: (i) 2NOCl (g)....