For the following equilibrium, Kc = | Class 11 Chemistry Chapter Equilibrium, Equilibrium NCERT Solutions

Question:

For the following equilibrium, K= 6.3 × 1014  at 1000 K

NO (g) + O3 (g) NO2 (g) + O2 (g)

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

Answer:

It is given that Kfor the forward reaction is 6.3 × 1014  

Then, K for the reverse reaction will be,

K = 1 / Kc

     = 1 /  6.3 × 1014  

     = 1.59 x 10-15


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Equilibrium.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Notice: Undefined index: quesId in /var/www/html/ss_beta/saralstudy/ss_new/web/template/common/comment_section.php on line 3

Comments

Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: For the following equilibrium, Kc = 6.3 × 1014  at 1000 K NO (g) + O3 (g) ↔ ....