For the following equilibrium, Kc = 6.3 × 1014 at 1000 K
NO (g) + O3 (g) ↔ NO2 (g) + O2 (g)
Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?
It is given that Kc for the forward reaction is 6.3 × 1014
Then, Kc for the reverse reaction will be,
K’c = 1 / Kc
= 1 / 6.3 × 1014
= 1.59 x 10-15
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: For the following equilibrium, Kc = 6.3 × 1014 at 1000 K NO (g) + O3 (g) ↔ ....
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