What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M ?
2ICl (g) ↔ I2 (g) + Cl2 (g); Kc = 0.14
The given reaction is:
2ICl (g) ↔ I2 (g) + Cl2 (g)
Initial conc. 0.78 M 0 0
At equilibrium (0.78 - 2x) M x M x M
Now we can write, Kc = I2 x Cl2 / (ICl)2
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 16: What is the equilibrium concentration of each of the substances in the equilibrium when the initial ....
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