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Two charged conducting spheres of radii | Class 12 Physics Chapter Electrostatic Potential and Capacitance, Electrostatic Potential and Capacitance NCERT Solutions

Q20.

Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.

Let a be the radius of a sphere A, QA be the charge on the sphere, and CA be the capacitance of the sphere. Let b be the radius of a sphere B, QB be the charge on the sphere, and CB be the capacitance of the sphere. Since the two spheres are connected with a wire, their potential (V) will become equal.

Let EA be the electric field of sphere A and EB be the electric field of sphere B. Therefore, their ratio,

Putting the value of (2) in (1), we obtain

Therefore, the ratio of electric fields at the surface is   

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Important Questions & Answers

What is the correct answer to: Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions.?

Let a be the radius of a sphere A, QA be the charge on the sphere, and CA be the capacitance of the sphere. Let b be the radius of a sphere B, QB be the charge on the sphere, and CB be the capacitance of the sphere. Sinc...

How do you solve Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatter portions. step by step?

Step-by-step explanation:
• Let a be the radius of a sphere A, QA be the charge on the sphere, and CA be the capacitance of the sphere
• Let b be the radius of a sphere B, QB be the charge on the sphere, and CB be the capacitance of the sphere
• Since the two spheres are connected with a wire, their potential (V) will become equal

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

physics Nerd
Class · · , · Jul 26, 2019
The second part of this question can be Explained by the phenomenon of Corona Discharge.
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Navpreet
Class · · , · Jan 27, 2019
Gud job
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