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  • Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

Light of wavelength 488 nm is produced b | Class 12 Physics Chapter Dual Nature Of Radiation And Matter, Dual Nature Of Radiation And Matter NCERT Solutions

Q11.

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

Wavelength of light produced by the argon laser, λ = 488 nm = 488 × 10−9 m

Stopping potential of the photoelectrons, V0 = 0.38 V

1eV = 1.6 × 10−19 J

∴ V0 = 0.38/1.6 x 10-19 eV

Planck’s constant, h = 6.6 × 10−34 Js

Charge on an electron, e = 1.6 × 10−19 C

Speed of light, c = 3 × 108 m/s

From Einstein’s photoelectric effect, we have the relation involving the work function Φ0 of the material of the emitter as: eV0 = hc/λ - ø0

∴ ø0 = hc/λ - eV0

= (6.6 x 10-34 x 3 x 108 / 1.6 x 10-19 x 488 x 10-9) - (1.6 x 10-19 x 0.38 / 1.6 x 10-19) = 2.54 - 0.38 = 2.16 eV

Therefore, the material with which the emitter is made has the work function of 2.16 eV.

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What is the correct answer to: Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.?

Wavelength of light produced by the argon laser, λ = 488 nm = 488 × 10−9 m

Stopping potential of the photoelectrons, V0 = 0.38 V

1eV = 1.6 × 10−19 J

∴ V0 = 0.38/1.6 x 10-19 ...

How do you solve Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made. step by step?

Step-by-step explanation:
• Wavelength of light produced by the argon laser, λ = 488 nm = 488 × 10−9 m

• Stopping potential of the photoelectrons, V0 = 0
• 38 V

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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