Assign the position of the element havin | Class 11 Chemistry Chapter Classification of Elements and Periodicity in Properties, Classification of Elements and Periodicity in Properties NCERT Solutions

Q30.

Assign the position of the element having outer electronic configuration

(i) ns2 np4 for n = 3 (ii) (n - 1)d2 ns2 for n = 4, and (iii) (n - 2) f7 (n - 1)d1 ns2 for n = 6, in the periodic table.

(i) Since n = 3, the element belongs to the 3rd period. It is a p–block element since the last electron occupies the p–orbital.

There are four electrons in the p–orbital. Thus, the corresponding group of the element

= Number of s–block groups (3s2) + number of d–block groups ([Ne]10 + number of p–electrons(3p4)

= 2 + 10 + 4

= 16

Therefore, the element belongs to the 3rd period and 16th group of the periodic table. Hence, the element is Sulphur ([Ne]103s23p4)

(ii) Since n = 4, the element belongs to the 4th period. It is a d–block element as d–orbitals are incompletely filled.

There are 2 electrons in the d–orbital.

Thus, the corresponding group of the element

= Number of s–block groups (4s2) + number of d–block groups (3d2)

= 2 + 2

= 4

Therefore, it is a 4th period and 4th group element. Hence, the element is Titanium ([Ar]183d24s2.

(iii) Since n = 6, the element is present in the 6th period. It is an f –block element as the last electron occupies the f–orbital. It belongs to group 3 of the periodic table since all f-block elements belong to group 3. Its electronic configuration is [Xe]54 4f7 5d1 6s2. Thus, its atomic number is 54 + 7 + 2 + 1 = 64. Hence, the element is Gadolinium.

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What is the correct answer to: Assign the position of the element having outer electronic configuration (i) ns2 np4 for n = 3 (ii) (n - 1)d2 ns2 for n = 4, and (iii) (n - 2) f7 (n - 1)d1 ns2 for n = 6, in the periodic table.?

(i) Since n = 3, the element belongs to the 3rd period. It is a p–block element since the last electron occupies the p–orbital.

There are four electrons in the p–orbital. Thus, the corresponding grou...

How do you solve Assign the position of the element having outer electronic configuration (i) ns2 np4 for n = 3 (ii) (n - 1)d2 ns2 for n = 4, and (iii) (n - 2) f7 (n - 1)d1 ns2 for n = 6, in the periodic table. step by step?

Step-by-step explanation:
• (i) Since n = 3, the element belongs to the 3rd period
• It is a p–block element since the last electron occupies the p–orbital


• There are four electrons in the p–orbital

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Student Discussion

Niharika
Class · · , · Jul 18, 2018
It is a good source of niformation to the childern of 11 (Che)we expect you to keep more and more like this
👍 👎 Reply
Muskan
Class · · , · Sep 03, 2017
For (n-1)d1ns2
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Mayank kumar
Class · · , · Nov 15, 2016
What is oxidation number of carbon's in CH3CH2O4
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Mayank kumat
Class · · , · Nov 15, 2016
Really helpful. Thanks
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