An ion with mass number 37 possesses one | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Q43.

An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

Let the number of electrons in the ion carrying a negative charge be x.

Then,

Number of neutrons present

= x + 11.1% of x

= x + 0.111 x

= 1.111 x

Number of electrons in the neutral atom = (x – 1)

(When an ion carries a negative charge, it carries an extra electron)

∴ Number of protons in the neutral atom = x – 1

Therefore 37 = 1.111x + x -1

Or 2.111 x = 38

Or x = 18

Therefore no of protons = atomic no = x -1 = 18 – 1 = 17

∴The symbol of the ion is 

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Important Questions & Answers

What is the correct answer to: An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.?

Let the number of electrons in the ion carrying a negative charge be x.

Then,

Number of neutrons present

= x + 11.1% of x

= x + 0.111 x

= 1.111 x

Number of electrons in the neutral atom = (x – 1)
...

How do you solve An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion. step by step?

Step-by-step explanation:
• Let the number of electrons in the ion carrying a negative charge be x


• Then,

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Nushtj
Class · · , · Sep 03, 2019
Hat
Bhag
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Arjun A
Class · · , · Dec 07, 2018
Thank you very much sir
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Subham
Class · · , · Oct 23, 2018
Very nice
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Divya
Class · · , · Sep 20, 2018
Thanku
😊
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Harshit
Class · · , · Jun 26, 2018
Thankuu
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Chandrakant jena
Class · · , · Jul 13, 2017
It is quite interesting that sir was today providing the facility for the cell studying student to get the solutions of their questions
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Animesh
Class · · , · Apr 26, 2017
How did u get x = 18
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