Calculate the temperature of 4.0 mol of | Class 11 Chemistry Chapter States of Matter, States of Matter NCERT Solutions

Question:

Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.

(R = 0.083 bar dm3 K–1 mol–1).

Answer:

Given,

Amount of the gas, n = 4.0 mol

Volume of the gas, V = 5 dm3

Pressure of the gas, p = 3.32 bar

R = 0.083 bar dm3 K–1 mol–1

From the ideal gas equation, we get

pV = nRT

T = pV / nR

      = (3.32x5) /  (4x0.083)

      = 50K

Hence, the required temperature is 50 K.


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Comments

  • Khushbu
  • 2019-03-16 19:15:46

Nice and easy solution , thanks


  • Kukkoo
  • 2019-02-03 19:32:55

Tq a lot . It helped me a lot . Upload question from subject chemistry of 2nd puc. Waiting.............


  • Tara
  • 2018-08-22 09:02:03

Its osm tqsm


  • Didikihmar
  • 2017-07-19 20:11:03

Please can you give me further answers???


  • kalpesh mali
  • 2016-07-04 22:24:47

pressure of gas filled in a closed cylinder 273k is 4 atm . calulate the temp of the gas when its pressure is 5 atm pleas send me the ans as soon as posible


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 12: Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K&n....