In terms of Charles’ law explain why –273°C is the lowest possible temperature.
Charles observed that the volume of certain amount of a gas changes by VO / 273.15 for each degree rise or fall in temperature.VO being the volume at 0°C.The volume at any temperature t°C is given by
Vt = VO(1 + t°C/ 273.15)
Now ,if the temperature is lowered, it becomes clear that at t = -273.15°C
Vt = VO(1+ (-273.15/273.15))
= VO = (1-1) = 0
And below t = -273.15°C, Vt becomes negative, which is not possible
Therefore the physically significant lowest temperature is -273.15° C
Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:
Isotope |
Isotopic molar mass |
Abundance |
36Ar |
35.96755 gmol–1 |
0.337% |
38Ar |
37.96272 gmol–1 |
0.063% |
40Ar |
39.9624 gmol–1 |
99.600% |
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 21: In terms of Charles’ law explain why –273°C is the lowest possible temperature.....
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