Pay load is defined as the difference between the mass of displaced air and the mass of the balloon. Calculate the pay load when a balloon of radius 10 m, mass 100 kg is filled with helium at 1.66 bar at 27°C. (Density of air = 1.2 kg m–3 and R = 0.083 bar dm3 K–1 mol–1).
Payload of the ballon = mass of the displaced air – mass of the ballon
Radius of the ballon, r = 10 m
Mass of the ballon, m = 100kg
Therefore volume of the ballon = 4/3πr3 = 4/3 x 22/7 x (10)3 = 4190.5 m3
Now volume of the displaced air = 4190.5 m3
Given,
Density of air = 1.2 kg m–3
Therefore, the mass of the displaced air
= 4190.5 x 1.2 = 5028.6 kg
Let w be the mass of helium gas filled into the ballon,then
PV = (w/m)RT
OR w = PVM/RT
= (1.66 X 4190.5 X 103 X 4) / (0.083 X 300)
= 1117 kg (approx)
Total mass of the balloon filled with He = 1117 + 100 = 1217 kg
Therefore payload of the balloon = 5028.6 – 1217 = 3811.6 kg
Hence, the pay load of the balloon is 3811.6 kg.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 16: Pay load is defined as the difference between the mass of displaced air and the mass of the balloon.....
Comments
Thank you for giving me this solution of this question in a very simple way
Thanks for doing this questions
Best