Calculate the standard enthalpy of forma | Class 11 Chemistry Chapter Thermodynamics, Thermodynamics NCERT Solutions

Question:

Calculate the standard enthalpy of formation of CH3OH(l) from the following data:

CH3OH (l) + 3/2 O2(g) → CO2(g) + 2H2O(l) ;   ΔrH0  = –726 kJ mol–1

C(g) + O2(g) → CO2(g) ;    ΔcH0 = –393 kJ mol–1

H2(g) + 1/2 O2(g) → H2O(l) ;    ΔfH0 = –286 kJ mol–1.

Answer:

The reaction that takes place during the formation of CH3OH(l) can be written as:

C(s) + 2H2O(g) + ½O2(g)  → CH3OH(l)     (1)

The reaction (1) can be obtained from the given reactions by following the algebraic calculations as:

Equation (ii) + 2 × equation (iii) - equation (i)

ΔfHθ [CH3OH(l)]  =  ΔcHθ  +  2ΔfHθ [H2O(l)]  - ΔrHθ

= (-393 kJ mol-1) + 2 (-286 kJ mol-1) - (-726 kJ mol-1)

= (-393 - 572 + 726) kJ mol-1

\therefore ΔfHθ[CH3OH(l)]

= -239 kJ mol-1


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 14: Calculate the standard enthalpy of formation of CH3OH(l) from the following data: CH3OH (l) + 3/2....