Three capacitors each of capacitance 9 pF are connected in series.
(a) What is the total capacitance of the combination?
(b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
(a) Capacitance of each of the three capacitors, C = 9 pF
Equivalent capacitance (C') of the combination of the capacitors is given by the relation,
Therefore, total capacitance of the combination is 3µF
(b) Supply voltage, V = 100 V
Potential difference (V') across each capacitor is equal to one-third of the supply voltage.
Therefore, the potential difference across each capacitor is 40 V.
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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: Three capacitors each of capacitance 9 pF are connected in series. (a) What is the total capacita....
Comments
it's value should be in pF.