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  • The plates of a parallel plate capacitor have an area of 90 cm2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply.

    (a) How much electrostatic energy is stored by the capacitor?

    (b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.

The plates of a parallel plate capacitor | Class 12 Physics Chapter Electrostatic Potential and Capacitance, Electrostatic Potential and Capacitance NCERT Solutions

Q26.

The plates of a parallel plate capacitor have an area of 90 cm2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply.

(a) How much electrostatic energy is stored by the capacitor?

(b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.

Area of the plates of a parallel plate capacitor, A = 90 cm2 = 90 × 10 - 4 m2

Distance between the plates, d = 2.5 mm = 2.5 × 10 - 3 m

Potential difference across the plates, V = 400 V

(a) Capacitance of the capacitor is given by the relation,

Electrostatic energy stored in the capacitor is given by the relation,

Where,

= Permittivity of free space = 8.85 × 10 - 12 C2 N - 1 m - 2

Hence, the electrostatic energy stored by the capacitor is 2.55 x 10-6 J

(b) Volume of the given capacitor,

Energy stored in the capacitor per unit volume is given by,

Where,

= Electric intensity = E

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What is the correct answer to: The plates of a parallel plate capacitor have an area of 90 cm2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply. (a) How much electrostatic energy is stored by the capacitor? (b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates.?

Area of the plates of a parallel plate capacitor, A = 90 cm2 = 90 × 10 - 4 m2

Distance between the plates, d = 2.5 mm = 2.5 × 10 - 3 m

Potential difference across the plates, V = 400 V

(a) Capacitanc...

How do you solve The plates of a parallel plate capacitor have an area of 90 cm2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply. (a) How much electrostatic energy is stored by the capacitor? (b) View this energy as stored in the electrostatic field between the plates, and obtain the energy per unit volume u. Hence arrive at a relation between u and the magnitude of electric field E between the plates. step by step?

Step-by-step explanation:
• Area of the plates of a parallel plate capacitor, A = 90 cm2 = 90 × 10 - 4 m2

• Distance between the plates, d = 2
• 5 mm = 2
• 5 × 10 - 3 m

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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