The photoelectric cut-off voltage in a c | Class 12 Physics Chapter Dual Nature Of Radiation And Matter, Dual Nature Of Radiation And Matter NCERT Solutions

Question:

The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?

Answer:

Photoelectric cut-off voltage, V0 = 1.5 V

The maximum kinetic energy of the emitted photoelectrons is given as: Ke = eVo

Where,

e = Charge on an electron = 1.6 × 10−19 C

∴ Ke = 1.6 x 10-19 x 1.5 = 2.4 x 10-19 J

Therefore, the maximum kinetic energy of the photoelectrons emitted in the given experiment is 2.4 × 10−19 J.

 

 

 

 

 


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Comments

  • Ambily
  • 2019-01-28 22:00:48

Thanq you so much


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic ener....