Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Chemical Bonding and Molecular Structure. This page offers a step-by-step solution to the specific question from Exercise 1, Question 38: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds?
Atomic number of Phosphorous is 15.
The Ground state configuration is
& the excited state configuration is
The 5 electrons present in valence shell form bond pairs with the electrons of five chlorine atoms. Phosphorus atom is sp3d hybridized in the excited state.
PCl5
The geometry of PCl5 is trigonal bipyramidal .The P atom lies in the centre of an equatorial triangle & three P-Cl bonds (equatorial bonds) are directed towards its three corners with 120° bond angle. The remaining two P-Cl bonds (axial bonds) lie above & below the plane of the triangle at bond angle 90° .
The axial bonds are longer than equatorial bonds because the axial Cl atoms suffer from more repulsion then the equatorial Cl atoms,as a result the axial Cl atoms tries to reside far away from the equatorial Cl atoms, & hence axial bond are longer than equatorial bonds.
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Read MoreWelcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 38: Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial....
Comments
Thanku
wrong config given... please correct
Orbital diagram of P atom
Formation of PCl5 molecule class11th
Define BMO and ABMO? How is it used to calculate bond order of the molecule???
Answer is right but electronic configuration is wrong because 3P have 3 degerated orbital and 3D have 5.
Answer is good but it electroni configuration is give wrong
Nice working with this answered
exelent...