Describe the hybridisation in case of PC | Class 11 Chemistry Chapter Chemical Bonding and Molecular Structure, Chemical Bonding and Molecular Structure NCERT Solutions

Q38.

Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds?

Atomic number of Phosphorous is 15.

The Ground state configuration is

& the excited state configuration is

The 5 electrons present in valence shell form bond pairs with the electrons of five chlorine atoms. Phosphorus atom is sp3d hybridized in the excited state.

PCl5

The geometry of PCl5 is trigonal bipyramidal .The P atom lies in the centre of an equatorial triangle & three P-Cl bonds (equatorial bonds) are directed towards its three corners with 120° bond angle. The remaining two P-Cl bonds (axial bonds) lie above & below the plane of the triangle at bond angle 90° .

 

The axial bonds are longer than equatorial bonds because the axial Cl atoms suffer from more repulsion then the equatorial Cl atoms,as a result the axial Cl atoms tries to reside far away from the equatorial Cl atoms, & hence axial bond are longer than equatorial bonds.

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What is the correct answer to: Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds??

Atomic number of Phosphorous is 15.

The Ground state configuration is



& the excited state configuration is



The 5 electrons present in valence shell form bond pairs with the electrons of five chlorine...

How do you solve Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds? step by step?

Step-by-step explanation:
• Atomic number of Phosphorous is 15
•
•
• The Ground state configuration is
•

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Gandheswari
Class · · , · Sep 24, 2019
Thanku
👍 👎 Reply
haha
Class · · , · Sep 13, 2019
wrong config given... please correct
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Prakash Pramanik
Class · · , · Nov 24, 2018
Orbital diagram of P atom
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Prakash Pramanik
Class · · , · Nov 24, 2018
Formation of PCl5 molecule class11th
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Vijay Hemanth
Class · · , · Sep 21, 2018
Define BMO and ABMO? How is it used to calculate bond order of the molecule???
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Adarsh Kumar singh
Class · · , · Apr 20, 2018
Answer is right but electronic configuration is wrong because 3P have 3 degerated orbital and 3D have 5.
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Bijay
Class · · , · Oct 20, 2017
Answer is good but it electroni configuration is give wrong
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pankaj Sharma
Class · · , · Oct 12, 2017
Nice working with this answered
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BHAVEY
Class · · , · Mar 10, 2016
exelent...
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