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  • A short bar magnet of magnetic moment 5.25 x 10-2J T-1is placed with its axis perpendicular to the earth's field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45º with earth's field on

    (a) its normal bisector and (b) its axis. Magnitude of the earth's field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.

A short bar magnet of magnetic moment 5. | Class 12 Physics Chapter Magnetism and Matter, Magnetism and Matter NCERT Solutions

Q15.

A short bar magnet of magnetic moment 5.25 x 10-2J T-1is placed with its axis perpendicular to the earth's field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45º with earth's field on

(a) its normal bisector and (b) its axis. Magnitude of the earth's field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.

Magnetic moment of the bar magnet, M= 5.25 ×10 - 2J T - 1

Magnitude of earth's magnetic field at a place, H= 0.42 G = 0.42 ×10 - 4T

(a) The magnetic field at a distance R from the centre of the magnet on the normal bisector is given by the relation:

Where, μ0= Permeability of free space = 4π ×10 - 7Tm A - 1

When the resultant field is inclined at 45°with earth's field, B= H

(b) The magnetic field at a distanced R' from the centre of the magnet on its axis is given as:

The resultant field is inclined at 45°with earth's field.

 

 

 

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What is the correct answer to: A short bar magnet of magnetic moment 5.25 x 10-2J T-1is placed with its axis perpendicular to the earth's field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45º with earth's field on (a) its normal bisector and (b) its axis. Magnitude of the earth's field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.?

Magnetic moment of the bar magnet, M= 5.25 ×10 - 2J T - 1

Magnitude of earth's magnetic field at a place, H= 0.42 G = 0.42 ×10 - 4T

(a) The magnetic field at a distance R from the centre of the mag...

How do you solve A short bar magnet of magnetic moment 5.25 x 10-2J T-1is placed with its axis perpendicular to the earth's field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45º with earth's field on (a) its normal bisector and (b) its axis. Magnitude of the earth's field at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved. step by step?

Step-by-step explanation:
• Magnetic moment of the bar magnet, M= 5
• 25 ×10 - 2J T - 1
•
• Magnitude of earth's magnetic field at a place, H= 0
• 42 G = 0

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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