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  • A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).

     

    (i) Express this in percent by mass.

     

    (ii) Determine the molality of chloroform in the water sample.

A sample of drinking water was found to | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Q17.

A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).

 

(i) Express this in percent by mass.

 

(ii) Determine the molality of chloroform in the water sample.

(i) 1 ppm is equivalent to 1 part out of 1 million (106) parts.

∴ Mass percent of 15 ppm chloroform in water

 

 

(ii) molality (M) = no of moles of solute/mass of solvent in g *1000

 

Therefore mass of chloroform= 12 + 1+3(35.5) = 119.5 g/mol

 

100 g of the sample contains 1.5 × 10–3 g of CHCl3.

 

⇒ 1000 g of the sample contains 1.5 × 10–2 g of CHCl3.

 

 m = 1.5 x 10-3/119.5 * 1000 = 1.25x 10-4 m

 

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Important Questions & Answers

What is the correct answer to: A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).   (i) Express this in percent by mass.   (ii) Determine the molality of chloroform in the water sample.?

(i) 1 ppm is equivalent to 1 part out of 1 million (106) parts.

∴ Mass percent of 15 ppm chloroform in water

 



 

(ii) molality (M) = no of moles of solute/mass of solvent in g *1000

&n...

How do you solve A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).   (i) Express this in percent by mass.   (ii) Determine the molality of chloroform in the water sample. step by step?

Step-by-step explanation:
• (i) 1 ppm is equivalent to 1 part out of 1 million (106) parts
•
•
• ∴ Mass percent of 15 ppm chloroform in water
•

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Rashmeet Kaur Khurana
Class · · , · Aug 05, 2020
Helpul.
👍 👎 Reply
Swayam
Class · · , · Aug 15, 2019
Thnx
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Tanvi Mishra
Class · · , · Aug 06, 2019
Overall,the method of solving problem is very easy and worth the explanation....
👍 👎 Reply
Emerald
Class · · , · Aug 03, 2019
All fine but the Molarity symbol
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Emerald
Class · · , · Aug 03, 2019
All fine but the symbol 😑
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Vishwesh
Class · · , · Jul 31, 2019
Good but learn molality symbol
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Atul Yadav
Class · · , · Jul 16, 2019
I didn't understand
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Anshit jaiswal
Class · · , · Jun 30, 2019
Solved nicely but M is not a symbol of the molality it should be m
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Varun
Class · · , · May 21, 2019
Really saral . Means very easy and helpful
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Piyush Chaturvedi
Class · · , · May 13, 2019
That's the answer I was looking for all along
Thank you Saralstudy
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